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Copy path47.全排列-ii.go
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47.全排列-ii.go
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import "sort"
/*
* @lc app=leetcode.cn id=47 lang=golang
*
* [47] 全排列 II
*
* https://leetcode-cn.com/problems/permutations-ii/description/
*
* algorithms
* Medium (52.11%)
* Likes: 100
* Dislikes: 0
* Total Accepted: 12K
* Total Submissions: 23K
* Testcase Example: '[1,1,2]'
*
* 给定一个可包含重复数字的序列,返回所有不重复的全排列。
*
* 示例:
*
* 输入: [1,1,2]
* 输出:
* [
* [1,1,2],
* [1,2,1],
* [2,1,1]
* ]
*
*/
func permuteUnique(nums []int) [][]int {
n := len(nums)
if n <= 0 {
return [][]int{}
}
if n == 1 {
return [][]int{
[]int{nums[0]},
}
}
sort.Ints(nums)
result := make([][]int, 0)
for i := len(nums) - 1; i >= 0; i-- {
if i != len(nums)-1 && nums[i] == nums[i+1] {
continue
}
leftResult := permuteUnique(removeKth(nums, i))
for _, items := range leftResult {
result = append(result, append(items, nums[i]))
}
}
return result
}
func removeKth(nums []int, k int) []int {
result := make([]int, 0)
for i, val := range nums {
if i != k {
result = append(result, val)
}
}
return result
}