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Hi, I have a LG G6 and As a side question, this device is supposed to support voltage up to 9V (and 1.8amp) in fast charge mode. Also my understanding is that 5V is the maximum voltage that an USB port normally gives, so I wonder why the limits are so small when charging. PS: I know using the maximum voltage is bad for the battery. |
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Lithium-based batteries are very sensitive to voltage and cannot tolerate overcharging at all - unlike, for instance, lead-acid batteries. The 4200 mV limit imposed by acc is a safety measure. Now let's talk about input vs charging powers. ACC does not limit what the power brick delivers. |
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voltage_max_design
, as the name implies, refers to the device's maximum charging voltage (not to be confused with input voltage - more on that later).The extra zeroes mean the unit is microvolt.
I have never seen volt being used.
It's usually either millivolt (e.g., 4350) or microvolt (4350000), for greater control/accuracy.
Lithium-based batteries are very sensitive to voltage and cannot tolerate overcharging at all - unlike, for instance, lead-acid batteries.
The former carry much higher risk of fire/explosion or rapid degradation when exposed to excessive voltage.
The 4200 mV limit imposed by acc is a safety measure.
It takes legacy batteries into account.
Originally, lithium-based ba…