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code-two-pointer-approach.cpp
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/* **************************************************************************
* Copyright 2024 The OpenGenus.org Authors. All Rights Reserved.
*
* Code for the book "DAILY 43: Algorithmic Problems for Coding Interviews: Easy level, C++ edition"
*
* Licensed under the GNU General Public License, Version 3.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.gnu.org/licenses/gpl-3.0.html
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*
* For details about the book, please visit: https://www.amazon.com/dp/B0CZJNBLQS
* *************************************************************************/
#include <iostream>
#include <string>
using namespace std;
// Two pointer approach
bool isSubsequence(string s, string t) {
int i = 0, j = 0;
// i is for first string S (subsequence)
// j is for second string T
while(i < s.length() && j < t.length()){
if(s[i] == t[j])
++i;
++j;
}
return i == s.length();
}
int main() {
// Example test cases
string s1 = "abc", t1 = "ahbgdc";
cout << "Is '" << s1 << "' a subsequence of '" << t1 << "'? "
<< (isSubsequence(s1, t1) ? "Yes" : "No") << endl;
string s2 = "axc", t2 = "ahbgdc";
cout << "Is '" << s2 << "' a subsequence of '" << t2 << "'? "
<< (isSubsequence(s2, t2) ? "Yes" : "No") << endl;
// Additional test cases
string s3 = "abc", t3 = "abcd";
cout << "Is '" << s3 << "' a subsequence of '" << t3 << "'? "
<< (isSubsequence(s3, t3) ? "Yes" : "No") << endl;
string s4 = "ace", t4 = "abcde";
cout << "Is '" << s4 << "' a subsequence of '" << t4 << "'? "
<< (isSubsequence(s4, t4) ? "Yes" : "No") << endl;
string s5 = "xyz", t5 = "xaybz";
cout << "Is '" << s5 << "' a subsequence of '" << t5 << "'? "
<< (isSubsequence(s5, t5) ? "Yes" : "No") << endl;
return 0;
}